-3(3x+1)=-[4x+(6x-5)]+x+7

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Solution for -3(3x+1)=-[4x+(6x-5)]+x+7 equation:


Simplifying
-3(3x + 1) = -1[4x + (6x + -5)] + x + 7

Reorder the terms:
-3(1 + 3x) = -1[4x + (6x + -5)] + x + 7
(1 * -3 + 3x * -3) = -1[4x + (6x + -5)] + x + 7
(-3 + -9x) = -1[4x + (6x + -5)] + x + 7

Reorder the terms:
-3 + -9x = -1[4x + (-5 + 6x)] + x + 7

Remove parenthesis around (-5 + 6x)
-3 + -9x = -1[4x + -5 + 6x] + x + 7

Reorder the terms:
-3 + -9x = -1[-5 + 4x + 6x] + x + 7

Combine like terms: 4x + 6x = 10x
-3 + -9x = -1[-5 + 10x] + x + 7
-3 + -9x = [-5 * -1 + 10x * -1] + x + 7
-3 + -9x = [5 + -10x] + x + 7

Reorder the terms:
-3 + -9x = 5 + 7 + -10x + x

Combine like terms: 5 + 7 = 12
-3 + -9x = 12 + -10x + x

Combine like terms: -10x + x = -9x
-3 + -9x = 12 + -9x

Add '9x' to each side of the equation.
-3 + -9x + 9x = 12 + -9x + 9x

Combine like terms: -9x + 9x = 0
-3 + 0 = 12 + -9x + 9x
-3 = 12 + -9x + 9x

Combine like terms: -9x + 9x = 0
-3 = 12 + 0
-3 = 12

Solving
-3 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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